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标题: 一个利用随机数加密字串的算法
选择自 rainstormmaster 的 Blog
关键字: vb, 随机数, 加密
首先这个算法没什么特殊之处,只是怕以后找不到,所以放到了这上面
每个字节加密后有6种结果(占两个字节,如果需要大于6种的话,就要多用1个字节,即占3 个字节),也就是说如果字串占n个字节的话,可能产生的结果为6的n次方个,这个算法破解的强度不大,大家可以完善一下:- '窗体上一个按钮,两个listbox
- Option Explicit
- Private Sub Command1_Click()
- Dim i As Long
- Dim s As String
- For i = 1 To 100
- s = encode("这是一个测试 hello world")
- List1.AddItem s
- s = decode(s)
- List2.AddItem s
- Next
- End Sub
- Private Function encode(ByVal s As String) As String '加密
- If Len(s) = 0 Then Exit Function
- Dim buff() As Byte
- buff = StrConv(s, vbFromUnicode)
- Dim i As Long
- Dim j As Byte
- Dim k As Byte, m As Byte
- Dim mstr As String
- mstr = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789abcdefghijklmnopqrstuvwxyz"
- Dim outs As String
- i = UBound(buff) + 1
- outs = Space(2 * i)
- Dim temps As String
- For i = 0 To UBound(buff)
- Randomize Time
- j = CByte(5 * (Math.Rnd()) + 0) '最大产生的随机数只能是5,不能再大了,再大的话,就要多用一个字节
- buff(i) = buff(i) Xor j
- k = buff(i) Mod Len(mstr)
- m = buff(i) \ Len(mstr)
- m = m * 2 ^ 3 + j
- temps = Mid(mstr, k + 1, 1) + Mid(mstr, m + 1, 1)
- Mid(outs, 2 * i + 1, 2) = temps
- Next
- encode = outs
- End Function
- Private Function decode(ByVal s As String) As String '解密
- On Error GoTo myERR
- Dim i As Long
- Dim j As Byte
- Dim k As Byte
- Dim m As Byte
- Dim mstr As String
- mstr = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789abcdefghijklmnopqrstuvwxyz"
- Dim t1 As String, t2 As String
- Dim buff() As Byte
- Dim n As Long
- n = 0
- For i = 1 To Len(s) Step 2
- t1 = Mid(s, i, 1)
- t2 = Mid(s, i + 1, 1)
- k = InStr(1, mstr, t1) - 1
- m = InStr(1, mstr, t2) - 1
- j = m \ 2 ^ 3
- m = m - j * 2 ^ 3
- ReDim Preserve buff(n)
- buff(n) = j * Len(mstr) + k
- buff(n) = buff(n) Xor m
- n = n + 1
- Next
- decode = StrConv(buff, vbUnicode)
- Exit Function
- myERR:
- decode = ""
- End Function
复制代码 作者Blog:http://blog.csdn.netainstormmaster/ |
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