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VB VBA ASP均可使用的通用Rsa加密和對應的解密函數

2017-09-19 09:17:00
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以下爲在VB VBA ASP均可使用的通用Rsa加密和對應的解密函數

先建立一箇類模塊 clsRsa


  Public PrivateKey 
  Public PublicKey 
  Public Modulus   
   
   
  Public Function Crypt(pLngMessage, pLngKey) 
    On Error Resume Next 
    Dim lLngMod 
    Dim lLngResult 
    Dim lLngIndex 
    If pLngKey Mod 2 = 0 Then 
      lLngResult = 1 
      For lLngIndex = 1 To pLngKey / 2 
        lLngMod = (pLngMessage ^ 2) Mod Modulus 
        ' Mod may error on key generation 
        lLngResult = (lLngMod * lLngResult) Mod Modulus 
        If Err Then Exit Function 
      Next 
    Else 
      lLngResult = pLngMessage 
      For lLngIndex = 1 To pLngKey / 2 
        lLngMod = (pLngMessage ^ 2) Mod Modulus 
        On Error Resume Next 
        ' Mod may error on key generation 
        lLngResult = (lLngMod * lLngResult) Mod Modulus 
        If Err Then Exit Function 
      Next 
    End If 
    Crypt = lLngResult 
  End Function 



  Public Function Encode(ByVal pStrMessage) 
    Dim lLngIndex 
    Dim lLngMaxIndex 
    Dim lBytAscii 
    Dim lLngEncrypted 
    lLngMaxIndex = Len(pStrMessage) 
    If lLngMaxIndex = 0 Then Exit Function 
    For lLngIndex = 1 To lLngMaxIndex 
      lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) 
      lLngEncrypted = Crypt(lBytAscii, PublicKey) 
      Encode = Encode & NumberToHex(lLngEncrypted, 4) 
    Next 
  End Function 
   
  Public Function Decode(ByVal pStrMessage) 
    Dim lBytAscii 
    Dim lLngIndex 
    Dim lLngMaxIndex 
    Dim lLngEncryptedData 
    Decode = "" 
    lLngMaxIndex = Len(pStrMessage) 
    For lLngIndex = 1 To lLngMaxIndex Step 4 
      lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4)) 
      lBytAscii = Crypt(lLngEncryptedData, PrivateKey) 
      Decode = Decode & Chr(lBytAscii) 
    Next 
  End Function 
   
  Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) 
    NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) 
  End Function 

  Private Function HexToNumber(ByRef pStrHex) 
    HexToNumber = CLng("&h" & pStrHex) 
  End Function 
再建立一箇模塊,放置如下VBA代碼



function Encryptstr(Message) 
Dim LngKeyE 
Dim LngKeyD 
Dim LngKeyN 
Dim StrMessage 
Dim ObjRSA 


  LngKeyE = "32823" 
  LngKeyD = "20643" 
  LngKeyN = "29893" 
  StrMessage = Message 
   
  Set ObjRSA = New clsRSA 
   
  
      ObjRSA.PublicKey = LngKeyE 
      ObjRSA.Modulus = LngKeyN 
      Encryptstr = ObjRSA.Encode(StrMessage) 
  Set ObjRSA = Nothing 
end function 




function decryptstr(Message) 
Dim LngKeyE 
Dim LngKeyD 
Dim LngKeyN 
Dim StrMessage 
Dim ObjRSA 


  LngKeyE = "32823" 
  LngKeyD = "20643" 
  LngKeyN = "29893" 
  StrMessage = Message 
   
  Set ObjRSA = New clsRSA 

      ObjRSA.PrivateKey =LngKeyD 
      ObjRSA.Modulus=LngKeyN 
      decryptstr=ObjRSA.Decode(StrMessage) 
  Set ObjRSA = Nothing 
end function 
然後就可以使用這箇加密 解密函數瞭


使用的測試代碼


dim strSrc,strDes
strSrc="sohu" 
Msgbox "加密前爲:"& strSrc
strDes=Encryptstr(strSrc) 
Msgbox  "加密後爲"& strDes
Msgbox "解密後爲" &decryptstr(strDes) 
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